<br><div class="gmail_quote"><br>Dear molpro developers and users,<br><div class="gmail_quote"><div><div class="h5"><br> I am trying to do the mrci
calculation for the first three states of ch3f+ ion which belongs to C3v
point group in the ground state. Since we can not deal with C3v point
group, <br> I must reduced its symmetry to cs by
replacing e symmetry with a',a''. <br> The ionized states are X2E and A2A1 in
C3v representation which will transform as X2A1, X2A2 and A2A1.<br>
<br><br> Reference coefficients greater than 0.0500000<br> -----------------------------</div></div><div>----------------<br><div><div><div></div><div class="h5"> 2222200220 0.9509877 -------- ground state X1A1 configuration<br>
<br> Reference coefficients greater than 0.0500000<br>
---------------------------------------------<br> 2222+00220 0.9449705 -------- X2A1 state configuration <br><br> Reference coefficients greater than 0.0500000<br> ---------------------------------------------<br>
22222002+0 0.9449723 -------- X2A2 state configuration<br>
<br> Reference coefficients greater than 0.0500000<br> ---------------------------------------------<br> 22+2200220
0.8066095 ----------- A2A1 state configuration
<<<<<<<<<<<<<<<<<<<<<
problematic <br>
<br>as u see above output the last configuration is not correct it
should give 222+200220. Now I want to fix it manually by specifying the
configuration of each state while calculating mrci. I read through the
manual and tried to fix it manually by using con card. But when I used
the following input job was terminating. <br>
<br>**,ionization potential<br>memory,100,m<br>basis={h=dz,c=cc-pvtz,f=aug-cc-pvtz}<br>geomtyp=xyz<br>geometry={5<br>equilibrium geometry<br>c 0.000000 0.000000 -0.636134<br>h 0.000000 1.029894 -0.984650<br>
h -0.891914 -0.514947 -0.984650<br>h 0.891914 -0.514947 -0.984650<br>f 0.000000 0.000000 0.752306<br>end}<br>rhf;occ,7,2;wf,18,1,0;orbital,2130.2;<br>multi;occ,9,3;closed,4,0;start,2130.2;wf,17,1,1;wf,17,2,1;save,2141.2;<br>
mrci;option,maxit=100;occ,9,3;closed,4,0;selcet,2141.2,con,2,2,2,2,1,0,0,2,2,0;wf,17,1,1;ref,2;<br>mrci;option,maxit=100;occ,9,3;closed,4,0;select,2141.2,con,2,2,2,2,2,0,0,2,1,0;wf,17,2,1;ref,1;<br>mrci;option,maxit=100;occ,9,3;closed,4,0;select,2141.2,con,2,2,2,1,2,0,0,2,2,0;wf,17,1,1;state,1,2;<br>
exit;<br><br>and the error message was <br><br>1PROGRAM * CI (Multireference internally contracted CI) Authors: H.-J. Werner, P.J. Knowles, 1987<br><br><br><br><b> NOT ENOUGH STATE VECTORS IN CONFIGURATION RECORD 2140.2. NEED: 2 FOUND: 0</b><br>
<br> ERROR EXIT<br> CURRENT STACK: CIINP CIPRO MAIN<br><br>Could you please provide correct format to fix the configuration.<br><br>Thanking you in advance for your help<br><br></div></div>Regards,<br>Aleem<br>Prof. Susanta Mahapatra Lab<br>
School of Chemistry,<br>University of Hyderabad,<br>INDIA.<br></div></div>
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