Bug?
Omololu
prayerz at yahoo.com
Mon Jun 9 20:02:35 BST 2003
Perhaps this is a "clearly demonstrable" program error
in MOLPRO. It is for a finite-field calculation for
CO2. I suspect it is something simple. The main parts
of the output are given below:
Including file /opt/molpro2002.3/lib/molproi.rc
***,CO2 hexadecapole
memory,20,m
GTHRESH, oneint=1.d-14, energy=1.d-9, step=1.d-5,
twoint=1.d-14, prefac=1.d-14
GTHRESH, coeff=1.0d-5, zero=1.0d-14
r1=1.162453 ang
r2=1.162453 ang
theta=180
geometry={nosym;C;
O1,C,r1;
O2,C,r2,O1,theta}
basis=avdz
expec,mltp4
hf;
f=[0.0001,-0.0001]
method=[hf,mp2]
k=0
do i=1,#f
field,zzzz,f(i)
do m=1,#method
k=k+1
$method(m)
core;
e(k)=energy
end do
end do
k=0
n=#method
do m=1,#method
k=k+1
hexz(m)=(e(k)-e(k+n))/(f(1)-f(2))
end do
table,method,hexz
title,hexadecapole (zzzz) result for CO2
---
1
*** PROGRAM
SYSTEM MOLPRO ***
Copyright,
University of Birmingham, 1997
Version 2002.3
linked 14 Oct 2002 14:37:52
**********************************************************************************************************************************
LABEL * CO2 HEXADECAPOLE
SunOS-5.9/strauss.udel.edu(sun4u) 64 bit version
DATE: 9-Jun-03
TIME: 14:44:50
**********************************************************************************************************************************
Point group C1
ATOMIC COORDINATES
NR ATOM CHARGE X Y
Z
1 C 6.00 0.000000000 0.000000000
0.000000000
2 O1 8.00 0.000000000 0.000000000
2.196717645
3 O2 8.00 0.000000000 0.000000000
-2.196717645
!RHF STATE 1.1 ENERGY -187.66239249
Nuclear energy 58.26875398
One-electron energy -372.06945424
Two-electron energy 126.13830776
Virial quotient -1.00194907
!RHF STATE 1.1 DIPOLE MOMENTS: 0.00000000
0.00000000 0.00000000
!RHF EXPECT. VALUE <1.1|XXXX|1.1> -30.89740128
A.U.
!RHF EXPECT. VALUE <1.1|XXYY|1.1> -10.29913376
A.U.
!RHF EXPECT. VALUE <1.1|XXZZ|1.1> -51.17419857
A.U.
!RHF EXPECT. VALUE <1.1|YYYY|1.1> -30.89740128
A.U.
!RHF EXPECT. VALUE <1.1|YYZZ|1.1> -51.17419857
A.U.
!RHF EXPECT. VALUE <1.1|ZZZZ|1.1> -277.37575790
A.U.
SETTING F(1:2) = 0.00010000
-0.00010000
SETTING METHOD(1) = HF
SETTING METHOD(2) = MP2
SETTING K = 0.00000000
DO I = 1.00000000
Reading unperturbed one-electron hamiltonian
?ERROR: FINITE FIELD PERTURBATION OPERATOR ZZZZ NOT
TOTALLY SYMMETRIC
ERROR EXIT
=====
***************** SEEK GOD! *******************
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