[molpro-user] inconsistent state numbering
Yann P. Tambouret
yannpaul at bu.edu
Fri Jul 15 14:29:29 BST 2005
If I understood the problem correctly your problem correctly, it can be
solved by using the 'root' array, made by Molpro. Once a CI calc is
done, this variable is created and it holds the root number of the ith
state (ordered by energy). So try something like
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!CI calc here
!transition moment calcs here
state1=root(1)+.1
state2=root(2)+.1
!ddr calc here
!everything the same, except:
mixing,state1,state2
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
You might need to use 'mixing,$state1,$state2''; I forget which is the
right way.
Good luck.
-Yann
William Chua wrote:
>Dear All,
>
>When I did
>
> ci;trans,savci+j,savci+j;
> dm,7000.2+j;
> ci;trans,savci+j,refci;
> dm,7100.2+j;
> ci;trans,savci+j,savci+1;
> dm,7200.2+j;
>
> ddr
> density,7000.2+j,7100.2+j
> orbital,3140.2+j,2140.2
> energy,eadia(1),eadia(2)
> mixing,1.1,2.1
>
>I got this error message
>
> Construct non-adiabatic coupling elements by finite
>difference method
>
> Orbitals at R from 3141.2
>Type=DIABATIC (state averaged)
> Orbitals at R+dR from 2140.2
>Type=NATURAL (state averaged)
>
> CENTER14 DISPLACED BY -1.551178 0.421122
>-0.915569
>
>
> Delta R 1.84980134
>
> Transition density (R|R) from 7001.2 for
>states 1.1 - 1.1
> Transition density (R|R+DR) from 7101.2 for
>states 1.1 - 1.1
>
> ?REQUESTED DENSITY NOT FOUND IN RECORD 7001.2 FOR
>STATE=201.1 TYPE(S)=TRANSITION
>
> THE RECORD CONTAINS THE FOLLOWING MRCI DATA:
> DENSITY/TRANSITION SET= 1 STATE=101.1 MS2=0
>NELEC= 6
> DENSITY/TRANSITION SET= 2 STATE=104.1 MS2=0
>NELEC= 6
> DENSITY/TRANSITION SET= 3 STATE=401.1 MS2=0
>NELEC= 6
> DENSITY/TRANSITION SET= 4 STATE=404.1 MS2=0
>NELEC= 6
>
> ERROR EXIT
> CURRENT STACK: MAIN
>
>because the state numbering in REFCI is 1.1, 2.1 but
>it's 1.1, 4.1 in SAVCI+j. At first I requested for
>default NSTATI (=NSTATE=2) but the CI calculation
>failed and at least NSTATI=4 is needed.
>
>Will anybody please suggest a way out?
>
>Thanks.
>
>Chua
>
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