[molpro-user] HOMO with PBE0
Yurii Vlasov
vlasov.yura at gmail.com
Sun Apr 11 20:25:08 BST 2010
Hello,
I'm new for MOLPRO. And I can't find the information how can I interpret the
notation:
Orbital energies:
1.1 2.1 3.1 4.1
5.1 6.1 7.1 8.1 9.1
-10.232785 -10.231846 -0.785055 -0.599287 -0.486936 -0.432784 -0.370832
0.004894 0.019761
1.2 2.2 3.2
-0.288898 -0.003594 0.059471
What does it mean: "1.1, 3.2, 9.1" and so on.
I need HOMO energy for c2h4 molecule with PBE0 potential. May be I should
add some keyword?
And my input file was the followng:
____________________
memory,100,m
geometry={angstrom
1 C1,, 0.,0.6695,0.
2 C2,, 0.,-0.6695,0.
3 H1,, -0.9291964775,1.229695418,0.
4 H2,, 0.9291964775,1.229695418,0.
5 H3,, 0.9291964775,-1.229695418,0.
6 H4,, -0.9291964775,-1.229695418,0.
}
basis=avtz
ks,pbe0
energ=dftfun
table,energ;digits,15
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