[molpro-user] DDR procedure
diwaker kumar
diwakerphysics at gmail.com
Fri Jun 14 15:17:29 BST 2013
Dear molpro users, i am using DDR procedure for calculating diabatication
for LICL, but i am getting constant values at every value of R as given
below
SETTING MIXCI(17) = 0.00000106
DEGREE
SETTING H11CI(17) = -466.86571465
AU
SETTING H21CI(17) = 0.00000000
AU
SETTING H22CI(17) = -466.66141158
AU
SETTING MIXTOT(17) = 0.00000106
DEGREE
SETTING H11(17) = -466.86571465
AU
SETTING H21(17) = 0.00000000
AU
SETTING H22(17) = -466.66141158
AU
Diabatic energies for Licl, obtained from CI-vectors
R E1 E2 H11CI H22CI
H21CI MIXCI
2.50 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.55 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.60 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.65 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.70 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.75 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.80 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.85 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.90 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
2.95 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
3.05 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
3.10 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
3.15 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
3.20 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
3.25 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
3.30 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
3.35 -466.86571465 -466.66141158 -466.86571465 -466.66141158
0.00000000 0.00
my input file will look like as
***,licl Diabatization
memory,64,m
gprint,orbitals,civector
symmetry,x,planeyz
orient,noorient
geometry={
li;
cl,li,r}
r=2.50
R=[2.50,2.55,2.60,2.65,2.70,2.75,2.80,2.85,2.90,2.95,3.05,3.10,3.15,3.20,3.25,3.30,3.35]
basis=avdz
reforb=2140.2
refci=6000.2
savci=6100.2
text,compute wavefunction at refrence geometry (C2v)
r1=r
{hf,
occ,8,2;
wf,20,1,0
orbital,2100.2}
{multi,
occ,9,2;closed,5,1;
wf,20,1;state,2;
natorb,reforb
noextra}
{ci,NOCHECK;
occ,9,2;closed,5,1;
wf,20,1,0;state,2;
option,nstati=10;
orbital,reforb
save,refci}
Text,Displaced geometries
do i=1,#R
data,truncate,savci+1
{multi;
occ,9,2;
closed,5,1;
wf,20,1,0;state,2;
start,reforb
orbital,3140.2;
diab,reforb
noextra}
{ci,NOCHECK;
occ,9,2;
closed,5,1;
option,maxiti=5000;
option,nstati=10;
wf,20,1,0;state,2;
orbital,diabatic
save,savci}
e1(i)=energy(1)
e2(i)=energy(2)
{ci;trans,savci,savci
dm,7000.2}
{ci;trans,savci,refci;
dm,7100.2}
{ddr
density,7000.2,7100.2
orbital,3140.2,2140.2
energy,e1(i),e2(i)
mixing,1.1,2.1}
mixci(i)=mixangci(1)
h11ci(i)=hdiaci(1)
h21ci(i)=hdiaci(2)
h22ci(i)=hdiaci(3)
mixtot(i)=mixang(1)
h11(i)=hdia(1)
h21(i)=hdia(2)
h22(i)=hdia(3)
{table,r,e1,e2,h11ci,h22ci,h21ci,mixci
title,Diabatic energies for Licl, obtained from CI-vectors
format,'(f10.2,5f14.8,f12.2)'
sort,1
plot,file='Licld1.plot'
}
{table,r,e1,e2,h11,h22,h21,mixtot
title,Diabatic energies for H2S, obtained from CI-vectors and orbital
correction
format,'(f10.2,5f14.8,f12.2)'
sort,1
plot,file='Licld2.plot'
}
enddo
i will be highly thankful if some one let me know where is the fault and
how to get rid of it
thanks in advance for your help
thanks
yours sincerely
Diwaker
Research Scholar
School of Basic sciences
Indian Institute of technology Mandi(H.P)
+919736660660
Email Id-:
diwakerphysics at gmail.com
diwakerphysics at yahoo.in
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