[molpro-user] Regarding CASSCF and MRCI calculation
Rameswar Bhattacharjee
rameswarb22 at gmail.com
Sat Jun 7 13:40:19 BST 2014
Dear all,
I am a new user of molpro.I want to calculate electronic configuration of
some low energy excited states.From the manual I understood that I need to
do casscf with mrci+q.So I made a input like following
******************************************************************
***,c4h4 !A titleu
symmetry,x,y,z
geomtyp=xyz
geometry={
8 ! number of atoms
This is an example of geometry input for c4h4 with an XYZ file
C 0.00000000 0.00000000 1.17016200
C 0.00000000 1.09120200 0.00000000
C 0.00000000 0.00000000 -1.17016200
C 0.00000000 -1.09120200 0.00000000
H 0.00000000 0.00000000 -2.24015600
H 0.00000000 -2.16119600 0.00000000
H 0.00000000 0.00000000 2.24015600
H 0.00000000 2.16119600 0.00000000
}
basis=6-31+g !use VTZ basis
hf
mrci !do mrci calculation
emrci_q=energd0(1)
************************************************************
But I am getting an error termination like
*************************************************************
Number of closed-shell orbitals: 4 ( 2 0 1 0 1 0 0 0 )
Number of active orbitals: 20 ( 6 2 4 1 4 1 2 0 )
Number of external orbitals: 52 ( 12 6 9 4 9 4 6 2 )
State symmetry 1
Number of electrons: 20 Spin symmetry=Singlet Space symmetry=0
Number of states: 1
Number of CSFs: 0 (3726839008 determinants, 34134779536
intermediate states)
?STATE SYMMETRY NOT POSSIBLE: 0
********************************************************************************
It will be my great pleasure if anybody suggest me how to calculate
electronic configuration of some low lying electronic states.Any suggestion
will be highly appreciated.
Best Regards
Rameswar Bhattacharjee
*********************************************************************
Rameswar Bhattacharjee
Junior Research Fellow
Dept. of Spectroscopy
Indian Association for the Cultivation of Science
Jadavpur, Kolkata-32
*********************************************************************
--
*Rameswar Bhattacharjee*
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