[molpro-user] Double minima problem of CaF ground state with MRCI
侯世林
slhou at ouc.edu.cn
Wed Jan 11 13:39:54 CET 2017
Dear Molpro users,
I am calculating the CaF ground state with MRCI/cc-pvxz (x=T,Q,5), and find there are two minima on its potential curve: one at Re(~2.0 angstrom), another at R=(2.5~2.6 angstrom). Active spaces are set from the default to {8,3,3} for nine active electrons.
I also try the ACPF approach; the results are similar to those of MRCI. Attached are the results and input file of ACPF/cc-pcvqz. Note with the ACPF/cc-pcv5z the second minima can be removed. But I think MRCI can give more physical data for this ground state.
Is there something wrong with my input file? How to remove it with MRCI approach?
Any comments and help are appreciated.
Thank you in advance,
Shilin Hou
Results(ACPF/cc-pcvqz):
R E1(HF) DIP1 E2(CASSCF) DIP2 E3(ACPF) DIP3
1.6 -776.2493090 0.17282959 -776.4200188 0.13818992 -776.5204776 0.23656468
1.8 -776.3148194 0.65163519 -776.4839416 0.60620805 -776.5804423 0.68439505
1.9 -776.3251340 0.88388333 -776.4937886 0.83099076 -776.5888267 0.90010015
2.0 -776.3269510 1.11353675 -776.4954508 1.05297386 -776.5893276 1.11336495
2.1 -776.3233233 1.34279372 -776.4920427 1.27395004 -776.5850192 1.32566006
2.2 -776.3163261 1.57322444 -776.4858342 1.49535523 -776.5781622 1.53696369
2.3 -776.3073476 1.80432337 -776.4788920 1.71816131 -776.5709855 1.74820085
2.4 -776.2973052 2.03726534 -776.4746510 1.94288730 -776.5681313 1.95872143
2.5 -776.2868008 2.27188611 -776.4804660 2.15765732 -776.5782443 2.16482483
2.6 -776.2762266 2.50854076 -776.4823416 2.37699001 -776.5861416 2.37097908
2.7 -776.2658324 2.74714894 -776.4760499 2.60049036 -776.5819935 2.58517957
2.8 -776.2557688 2.98754186 -776.4673357 2.82661062 -776.5738194 2.80337286
***, CaF ground state
r=[ 1.6 1.8 1.9 2.0 2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 ] ang
do l=1,#r
geometry={F;Ca,F,$r(l)}
basis=cc-pcvqz
!basis=cc-pcv5z
{ hf
occ,9,3,3
closed, 8,3,3
wf,29,1,1 }
e(1) = energy
method(1) = program
dip(1) = dmz
bond(1) = $r(l)
e1(l)= energy
dip1(l)= dmz
{casscf
occ,14,5,5
closed, 6,2,2
frozen,6,2,2
maxiter,40
wf,29,1,1
orbital,2140.2 }
e(2) = energy
method(2) = program
dip(2) = dmz
bond(2) = $r(l)
e2(l)= energy
dip2(l)= dmz
! {MRCI
{acpf
occ,14,5,5
closed, 6,2,2
core,6,2,2
maxiter,200,200
wf,29,1,1
orbital,2140.2 }
e(3) = energy
method(3) = program
dip(3) = dmz
bond(3) = $r(l)
e3(l)= energy
dip3(l)= dmz
table,method,bond,e,dip
enddo
table, r,e1,dip1, e2,dip2,e3,dip3
---
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