[molpro-user] puzzling XeF2 result
Hoffman, Gerald
GHOFFMAN at edinboro.edu
Mon Jul 24 21:57:28 CEST 2017
Using the input file below, I attempted an SCF calculation on the XeF2 molecule using the Stuttgart ECP and basis set for Xe and the Aug-cc-pVQZ basis set for F. I obtained a total energy of -45.33 Hartrees. This is clearly wrong. Each of the fluorines by itself ought to have an energy of -99. Hartrees, and in previous versions of Molpro, the energy of this molecule is around -214. Hartrees. The calculation of XeF gives a reasonable value (-115. Hartrees).
Help would be appreciated.
Input file:
***,XeF2
memory,50,M
angstrom
geometry={
Xe 0.0000 0.0000 0.0000
F1 0.0000 0.0000 -1.99
F2 0.0000 0.0000 1.99
}
basis={
!
! Xenon ecp
!
ecp,Xe,46,5,3;
1; ! h
2,1.00,0.00
2; ! s-h
2,3.940263,122.76382934;2,2.277264,8.30885115;
2; ! p-h
2,3.028373,68.82300437;2,1.394319,3.64674233;
2; ! d-h
2,2.122605,23.65207854;2,0.798669,3.25844113;
2; ! f-h
2,6.164360,-47.70319876;2,1.542374,-6.54113991;
1; ! g-h
2,1.847892,-7.10585060;
2; ! so-ecp
2,3.028373,-1.74609113*(2/3);2,1.394319,2.19487257*(2/3);
2; ! so-ecp
2,2.122605,-1.04567591*(2/5);2,0.798669,0.27199291*(2/5);
1; ! so-ecp
2,6.164360,0.20772207*(2/7);
!
! Xenon basis
!
spdfg,Xe,ecp46mwb_vqz
s,Xe,0.040702,0.019340;c,1.1,1.00;c,2.2,1.00;
p,Xe,0.026108,0.012447;c,1.1,1.00;c,2.2,1.00;
d,Xe,0.089444;c,1.1,1.00;
f,Xe,0.132301;c,1.1,1.00;
!
! Fluorine-basis
!
spdfg,F,avqz
s,2,0.034376;c,1.1,1.00;
p,2,0.026272;c,1.1,1.00;
d,2,0.0828;c,1.1,1.00;
}
cpp,init,1;
Xe,1,0.8345,,,0.97391;
{rhf;wf,16,1,0;}
Gerry Hoffman
Gerald J. Hoffman, Ph. D.
Associate Professor of Chemistry
Edinboro University of Pennsylvania
230 Scotland Road
Edinboro, PA 16444
814-732-2813
ghoffman at edinboro.edu<mailto:ghoffman at edinboro.edu>
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